Convert decimal to binary in C

Question

I am trying to convert a decimal to binary such as 192 to 11000000. I just need some simple code to do this but the code I have so far doesn\'t work:

void de         


        

Answer 1

Perhaps understanding the algorithm would allow you write or modify your own code to suit what you need. I do see that you don't have enough char array length to display your binary value for 192 though (You need 8 digits of binary, but your code only gives 5 binary digits)

Here's a page that clearly explains the algorithm.

I'm not a C/C++ programmer so here's my C# code contribution based on the algorithm example.

int I = 0;
int Q = 95;
string B = "";
while (Q != 0)
{
    Debug.Print(I.ToString());
    B += (Q%2);
    Q = Q/2;
    Debug.Print(Q.ToString());
    I++;
}

Debug.Print(B);

All the Debug.Print is just to show the output.

Answer 2

//decimal to binary converter
long int dec2bin(unsigned int decimal_number){
  if (decimal_number == 0)
    return 0;
  else
    return ((decimal_number%2) + 10 * dec2bin(decimal_number/2));
}

Answer 3

So... did you check the output of your code to understand why it doesn't work?

So iteration 1 of your loop:
value = 192
i = 4
output[i] = (11000000 & 1) + '0' = 0 + 48 = 48 (char `0`)

Iteration 2 of your loop:
value = 96
i = 3
output[i] = (1100000 & 1) + '0' = 0 + 48 = 48 (char `0`)

Iteration 3 of your loop:
value = 48
i = 2
output[i] = (110000 & 1) + '0' = 0 + 48 = 48 (char `0`)

Iteration 4 of your loop:
value = 24
i = 1
output[i] = (11000 & 1) + '0' = 0 + 48 = 48 (char `0`)

Iteration 5 of your loop:
value = 12
i = 0
output[i] = (1100 & 1) + '0' = 0 + 48 = 48 (char `0`)

Final string: "00000"  and you wanted: "11000000"

See anything wrong with your code? Nope. Neither do I you just didn't go far enough. Change your output/loop to:

output[8] = '\0';
for (i = 7; i >= 0; --i, value >>= 1)

And then you'll have the correct result returned.

I would recomend just a more general approach, you're using a fixed length string, which limits you to binary numbers of a certian length. You might want to do something like:

loop while number dividing down is > 0
count number of times we loop
malloc an array the correct length and be returned

Answer 4

5 digits are not enough for your example (192). Probably you should increase output

Answer 5

Convert Decimal to Binary in C Language

#include<stdio.h>
void main()
{
    long int n,n1,m=1,rem,ans=0;
    printf("\nEnter Your Decimal No (between 0 to 1023) :: ");
    scanf("%ld",&n);

    n1=n;
    while(n>0)
    {
        rem=n%2;
        ans=(rem*m)+ans;
        n=n/2;
        m=m*10;
    }

    printf("\nYour Decimal No is   :: %ld",n1);
    printf("\nConvert into Binary No is :: %ld",ans);
}

Answer 6

This is the simplest way to do it

#include <stdio.h>

void main()
{
    int n,i,j,sum=0;
    printf("Enter a Decimal number to convert it to binary : ");
    scanf("%d",&n);
    for(i=n,j=1;i>=1;j*=10,i/=2)
        sum+=(i%2)*j;
    printf("\n%d",sum);
}