I have a big file (19GB or so) that I want to load in memory to perform an aggregation over some columns.
the file looks like this:
id, col1, col2,
Firstly you can choose list of unique constants by read csv with usecols - usecols=['id', 'col1']
. Then read csv by chunks, concat chunks by subset of id and groupby. better explain.
If better is use column col1
, change constants = df['col1'].unique().tolist()
. It depends on your data.
Or you can read only one column df = pd.read_csv(io.StringIO(temp), sep=",", usecols=['id'])
, it depends on your data.
import pandas as pd
import numpy as np
import io
#test data
temp=u"""id,col1,col2,col3
1,13,15,14
1,13,15,14
1,12,15,13
2,18,15,13
2,18,15,13
2,18,15,13
2,18,15,13
2,18,15,13
2,18,15,13
3,14,15,13
3,14,15,13
3,14,185,213"""
df = pd.read_csv(io.StringIO(temp), sep=",", usecols=['id', 'col1'])
#drop duplicities, from out you can choose constant
df = df.drop_duplicates()
print df
# id col1
#0 1 13
#2 1 12
#3 2 18
#9 3 14
#for example list of constants
constants = [1,2,3]
#or column id to list of unique values
constants = df['id'].unique().tolist()
print constants
#[1L, 2L, 3L]
for i in constants:
iter_csv = pd.read_csv(io.StringIO(temp), delimiter=",", chunksize=10)
#concat subset with rows id == constant
df = pd.concat([chunk[chunk['id'] == i] for chunk in iter_csv])
#your groupby function
data = df.reset_index(drop=True).groupby(["id","col1"], as_index=False).sum()
print data.to_csv(index=False)
#id,col1,col2,col3
#1,12,15,13
#1,13,30,28
#
#id,col1,col2,col3
#2,18,90,78
#
#id,col1,col2,col3
#3,14,215,239
Dask.dataframe can almost do this without modification
$ cat so.csv
id,col1,col2,col3
1,13,15,14
1,13,15,14
1,12,15,13
2,18,15,13
2,18,15,13
2,18,15,13
2,18,15,13
2,18,15,13
2,18,15,13
3,14,15,13
3,14,15,13
3,14,185,213
$ pip install dask[dataframe]
$ ipython
In [1]: import dask.dataframe as dd
In [2]: df = dd.read_csv('so.csv', sep=',')
In [3]: df.head()
Out[3]:
id col1 col2 col3
0 1 13 15 14
1 1 13 15 14
2 1 12 15 13
3 2 18 15 13
4 2 18 15 13
In [4]: df.groupby(['id', 'col1']).sum().compute()
Out[4]:
col2 col3
id col1
1 12 15 13
13 30 28
2 18 90 78
3 14 215 239
No one has written as_index=False
for groupby though. We can work around this with assign
.
In [5]: df.assign(id_2=df.id, col1_2=df.col1).groupby(['id_2', 'col1_2']).sum().compute()
Out[5]:
id col1 col2 col3
id_2 col1_2
1 12 1 12 15 13
13 2 26 30 28
2 18 12 108 90 78
3 14 9 42 215 239
We'll pull out chunks and do groupbys just like in your first example. Once we're done grouping and summing each of the chunks we'll gather all of the intermediate results together and do another slightly different groupby.sum
. This makes the assumption that the intermediate results will fit in memory.
As a pleasant side effect, this will also operate in parallel.