PHP Calculating future date by adding days to a variable date

Question

I was looking at this post, and it is close to what I need: PHP - How to count 60 days from the add date

However, in that post, the calculation is performed by addi

Answer 1

Use date_add

http://www.php.net/manual/en/datetime.add.php

$my_date = new DateTime($some_row_from_a_database);
$date_plus_10_days = date_add($my_date, new DateInterval('P10D'));

Answer 2

You can put something before the "+10 days" part:

strtotime("2010-01-01 +10 days");

Answer 3

date('Y-m-d H:i:s', strtotime("2014-11-24 06:33:39" +35 days"))

this will get the calculated date in defined format.

Answer 4

You will have to look into strtotime(). I'd imagine your final code would look something like this:

$dateVariable      = strtotime('2017-01-29');//your date variable goes here
$date_plus_60_days = date('Y-m-d', strtotime('+ 60 days', $dateVariable));
echo $date_plus_60_days;

If you are using PHP >= 5.2 I strongly suggest you use the new DateTime object. For example like below:

$date_plus_60_days = new DateTime("2006-12-12");
$date_plus_60_days->modify("+60 days");
echo $date_plus_60_days->format("Y-m-d");

Answer 5

Suppose today's date is

date_default_timezone_set('Asia/Calcutta');
$today=date("Y-m-d");

And i can add 10 days in current date as follows :

$date_afte_10_days = date('Y-m-d', strtotime("$today +10 days"));

Answer 6

I see you are retriving data from a database. If you are using mysql you can do it on the select:

Example: you need the last date of the table and this date-7 days

select max(datefield) as ultimaf, DATE_SUB(max(datefield),INTERVAL 7 DAY) as last7
from table

It´s easy use curdate() if you want todays date.

If you need a dynamic between that selects the count of last 7 days:

select count(*) from table
where DATE_SUB(CURDATE(),INTERVAL 7 DAY)<=datefield"