Getting the Action of UIGestureRecognizer in iOS

Question

I have printed a UITableviewCell\'s gesture in – tableView:didSelectRowAtIndexPath method in NSLog as

Answer 1

I have a different solution to this which has worked for me. This is more of a design change... you cannot access the target from the captured gesture. So instead keep a reference to the object when the touch down happened and before the pan began.

@property (nonatomic, strong) UIButton *myTouchedButton; // reference to button

(void)init
{
    ...
    [card.button addTarget:self action:@selector(cardTouchDownInside:) forControlEvents:UIControlEventTouchDown];
    ...
}

-(void)cardTouchDownInside:(id)sender
{
    NSLog(@"touch down on object");
    self.myTouchedButton = (UIButton*)sender;
}

Answer 2

UIGestureRecognizer internally maintains an array of targets. There is no public access to this array.

Answer 3

There is a way to gain access to the property target, but I'm not sure that this method will pass the Apple approval process.

NSMutableArray *targets = [myGes valueForKeyPath:@"_targets"];
id targetContainer = targets[0];//get first target for example
id targetOfMyGes = [targetContainer valueForKeyPath:@"_target"];
NSLog(@"%@", targetOfMyGes );//you can see reference for target object

Thanks neilco - his answer help create solution.

Note: the exact class of the object targetOfMyGes need to define yourself. By default it id - suitable for any object class.