Converting byte array values in little endian order to short values

Question

I have a byte array where the data in the array is actually short data. The bytes are ordered in little endian:

3, 1, -48, 0, -15, 0, 36, 1

Which when conver

Answer 1

With java.nio.ByteBuffer you may specify the endianness you want: order().

ByteBuffer have methods to extract data as byte, char, getShort(), getInt(), long, double...

Here's an example how to use it:

ByteBuffer bb = ByteBuffer.wrap(byteArray);
bb.order( ByteOrder.LITTLE_ENDIAN);
while( bb.hasRemaining()) {
   short v = bb.getShort();
   /* Do something with v... */
}

Answer 2

 /* Try this: */
public static short byteArrayToShortLE(final byte[] b, final int offset) 
{
        short value = 0;
        for (int i = 0; i < 2; i++) 
        {
            value |= (b[i + offset] & 0x000000FF) << (i * 8);
        }            

        return value;
 }

 /* if you prefer... */
 public static int byteArrayToIntLE(final byte[] b, final int offset) 
 {
        int value = 0;

        for (int i = 0; i < 4; i++) 
        {
           value |= ((int)b[i + offset] & 0x000000FF) << (i * 8);
        }

       return value;
 }