Spring data jpa save can not get id

Question

My entity id is generated, and it was working fine when I use DAO instead of Spring data JPA.

@Id
@Column(name = TABLE_COLUM_NAME_ID)
@GeneratedValue
private         


        

Answer 1

I finally figured it out. Even though the save method is void, you can set a variable to it.(?)

    @PostMapping(value = "customer/{id}/wish/add")
public String processAddWish(Model model, @PathVariable int id,
                             @ModelAttribute @Valid WishOrder newWishOrder,
                             Errors errors) {
    if (errors.hasErrors()) {
        return "customer/wish/add";
    }
    //Initialize variable to the save method, even though it is void and returns nothing//
    //Eliminates need to access object through a .findById//
    //If you need the id of the saved object instantly, just add .getId to save call//
    //wishOrderDao.save(newWishOrder).getId()//
    WishOrder wish = wishOrderDao.save(newWishOrder);
    Customer customer = customerDao.findById(id);
    customer.getWishList().add(wish);
    customerDao.save(customer);

    model.addAttribute("customer",(customer));
    model.addAttribute("wishList", (customer.getWishList()));

    return "customer/wishList";
}

Answer 2

This method returns the saved id

myobject = repository.saveAndFlush(myobject);

Now you have your id.

Answer 3

I guess you didn't have a @Transactional annotation on your Service method.

Answer 4

Try specifying strategy for @GeneratedValue like

@GeneratedValue(strategy = GenerationType.AUTO)

Answer 5

I believe this post answers your question:

Why to use returned instance after save() on Spring Data JPA Repository?

The repository.save() method actually returns a new object like JPA entityManager.merge() and the returned object is the one that will have the ID set.

Answer 6

Try this like

myboject = repository.save(myboject);
repository.flush();

Then after call to getId();