Nested Loop Python

Question

count = 1
for i in range(10):
    for j in range(0, i):
        print(count, end=\'\')
        count = count +1
    print()
input()

I am writing a

Answer 1

Change print(count, end='') to print(i + 1, end='') and remove count. Just make sure you understand why it works.

Answer 2

Is this what you want:

for i in range(10):
    print(str(i) * i)

Answer 3

"""2. 111 222 333 printing"""

for l in range (1,10):
    for k in range(l):
        print(l,end='')
print()

Answer 4

count = 1
for i in range(9):
    for j in range (-1, i):
        print (count, end = '')
    count = count + 1
    print (" ")

Answer 5

The simple mistake in your code is the placement of count = count + 1. It should be placed after the second for loop block. I have made a simple change in your own code to obtain the output you want.

    from __future__ import print_function
    count = 0
    for i in range(10):
        for j in range(0, i):
            print(count,end='')
        count = count +1
    print()

This will give the output you want with the code you wrote. :)

Answer 6

This is one line solution. A little bit long:

print ('\n'.join([str(i)*i for i in range(1,10)]))