Use a Java application as the Default Program for a particular file type?

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南方客
南方客 2020-12-09 20:30

I have created a text editor using Java, and have it packed in a jar file using Netbeans. Now I created a text file, with an extension of \".text\". I\'m on Windows 7, so us

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  • 2020-12-09 20:55

    The problem is that a JAR file is selected as the "default application". However, JAR files are normally not executable. That is, a JAR file is not a valid Windows application. It doesn't matter if the JAR extension itself has a default application associated with it, because the "Open verb" is not used recursively in other "Open verb" definitions.

    Instead,

    1. Create a batch (".BAT") file (or small EXE wrapper) that calls java (or javaw, as appropriate) and use that executable wrapper as the "Open with" program. (This will have an annoying intermediate console window if using a batch file.) Or,
    2. Modify the registry so that the "Open verb" for the extension launches the JAR through java (or javaw).

    In the end, either form should look similar to: javaw -jar TheJarFile.jar "%1%". (Note that javaw is an executable, while TheJarFile.jar is not an executable.)

    See java - the Java application launcher for how to use java/javaw.

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  • 2020-12-09 21:05

    May be because .text is not an executable file.

    try using this..

    Runtime.getRuntime().exec("cmd.exe /C file");
    

    This will open your file with the default program.

    Update: I got confused first, may be I didn't read your question properly. I thought your executing .text file directly from a Java code..

    Runtime.getRuntime().exec("file.text"); //Gives error CreateProcess error=193, %1 is not a valid Win32 application

    So I suggested opening it with cmd(as in answer).

    But reading your scenario, it seems windows is unable to execute your jar itself.

    To make your jar executable, try this..

    java -jar yourjarfile.jar....

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