This is the function I\'m trying to write:
function getWednesdays($month, $year) {
// Returns an array of DateTimes representing all Wednesdays this month
You can try something like this:
function getWednesdays($month, $year) {
$base_date = strtotime($year . '-' . $month . '-01');
$wed = strtotime('first wed of ' . date('F Y', $base_date));
$wednesdays = array();
do {
$wednesdays[] = new DateTime(date('r', $wed));
$wed = strtotime('+7 days', $wed);
} while (date('m', $wed) == $month);
return $wednesdays;
}
<?php
function wednesdays($month, $year)
{
list($n,$d) = explode('-', date('t-d', strtotime("Wednesday, $year-$month")));
$days = array();
while ($d <= $n)
{
$days[] = sprintf("%04d-%02d-%02d", $year, $month, $d);
$d += 7;
}
return $days;
}
var_dump(wednesdays(11, 2010));
?>
But I highly recommend getting used to PHP 5.3's date and time functions if you can use them. (See Gordon's answer.)
Here is the sample
function getSundays($y,$m){
$date = "$y-$m-01";
$first_day = date('N',strtotime($date));
$first_day = 7 - $first_day + 1;
$last_day = date('t',strtotime($date));
$days = array();
for($i=$first_day; $i<=$last_day; $i=$i+7 ){
$days[] = $i;
}
return $days;
}
$days = getSundays(2016,04);
print_r($days);
With PHP5.3
function getWednesdays($y, $m)
{
return new DatePeriod(
new DateTime("first wednesday of $y-$m"),
DateInterval::createFromDateString('next wednesday'),
new DateTime("last day of $y-$m")
);
}
Usage:
foreach (getWednesdays(2010, 11) as $wednesday) {
echo $wednesday->format("l, Y-m-d\n");
}
Output:
Wednesday, 2010-11-03
Wednesday, 2010-11-10
Wednesday, 2010-11-17
Wednesday, 2010-11-24
Note that this will exclude the end date, so if the last day of $y-$m
happens to be a Wednesday, it won't be in the list. You have to add a day to the end date, to include it. To include it, change the relative format in the end date to
new DateTime("next month $y-$m-01")
which will then set the end date to the first day of the next month,
With PHP < 5.3
function getWednesdays($y, $m)
{
$ts = strtotime("first wednesday $y-$m-01");
$end = strtotime("last wednesday $y-$m");
$wednesdays = array();
while($ts <= $end) {
$wednesdays[] = $ts;
$ts = strtotime('next wednesday', $ts);
}
return $wednesdays;
}
Usage:
foreach (getWednesdays(2010, 11) as $wednesday) {
echo date("l, Y-m-d\n", $wednesday);
}
Same output as above (Run on Codepad).
Note that this does not work for any version prior to 5.3 due to changes in the relative formats parser. If you want to use this with PHP 5.3+ you have to change first Wednesday $y-$m-01
to first Wednesday of $y-$m-01
(mind the "of"). Also, just like in the DateTime version, the end date will not be included.
Further reading:
Use this function to get any days total count in a month
function getTotalDays($year, $month, $day){
$from = $year."-".$month."-01";
$t=date("t",strtotime($from));
for($i=1; $i<$t; $i++){
if( strtolower(date("l",strtotime($year."-".$month."-".$i)))== $day){
$count++;
}
}
return $count;
}
use like this getTotalDays('2014', '08','monday');
will output 4
But if you want all dates in a month on a particular day then use this function
function getTotalDatesArray($year, $month, $day){
$date_ar=array();
$from = $year."-".$month."-01";
$t=date("t",strtotime($from));
for($i=1; $i<$t; $i++){
if( strtolower(date("l",strtotime($year."-".$month."-".$i)))== $day){
$j= $i>9 ? $i: "0".$i;
$date_ar[]=$year."-".$month."-".$j;
}
}
return $date_ar;
}
use like this getTotalDatesArray('2014', '08','monday');
will output Array ( [0] => 2014-08-04 [1] => 2014-08-11 [2] => 2014-08-18 [3] => 2014-08-25 )