SQL: Select most recent date for each category

Question

I\'m pulling data from a database and one of the tables contain two columns that together identify a location and another column containing a date of each time it was servic

Answer 1

Try

select category_a, category_b, max(date) as last_update from table group by category_a, category_b

Answer 2

SELECT
    category_a,
    category_b,
    MAX(date)
FROM
    Some_Unnamed_Table
GROUP BY
    category_a,
    category_b
ORDER BY
    category_a,
    category_b

I certainly don't mind helping people when I can, or I wouldn't be on this site, but did you really search for an answer for this before posting?

Answer 3

select category_a, category_b, max( date) from tbl group by category_a ,category_b;

Answer 4

This is a simple "group by" using the fact the the "most recent" date is the "highest valued", or max(), date

select category_a, category_b, max(date)
from mytable
group by category_a, category_b
order by category_a, category_b -- The ORDER BY is optional, but the example data suggests it's needed