Drawing a hollow asterisk square

Question

I\'m trying to figure out how to turn my whole square into a hollow one. The few things I\'ve tried so far haven\'t been very successful as I end up getting present

Answer 1

Here is my python code for drawing a square by entered size N.

n = int(input())
print('*' * n)
for i in range(n-2):
    print ('*' + ' ' * (n-2) + '*')
print('*' * n)

Basically the first and the last print('*' * n) are drawing the top and the bottom lines and the for cycle prints the body.

Output example: N=3

***
* *
***

Output example: N=5

*****
*   *
*   *
*   *
*****

Answer 2

def emptySquare(length,char):
    for i in range(length):
        for j in range(length):
            if (i == 0 or i == length-1 or j == 0 or j == length-1):
                print(char,end=" ")
            else:
                print(" ",end=" ")
        print()

Answer 3

I think this is what you want to do:

m, n = 10, 10
for i in range(m):
    for j in range(n):
        print('*' if i in [0, n-1] or j in [0, m-1] else ' ', end='')
    print()

Output:

**********
*        *
*        *
*        *
*        *
*        *
*        *
*        *
*        *
**********

You can also draw a triangle this way:

m, n = 10, 10
for i in range(m):
    for j in range(n):
        print('*' if i in [j, m-1] or j == 0 else ' ', end='')
    print()

Output:

*         
**        
* *       
*  *      
*   *     
*    *    
*     *   
*      *  
*       * 
**********

Answer 4

Heres my example:

print("Enter width")
width = int(input())
print("Enter height")
height = int(input())

for i in range(height):
    if i in[0]:
        print("* "*(width))
    elif i in[(height-1)]:
        print("* "*(width))
    else:
        print("*"+"  "*(width-2)+" *")

input()

Output: Image link

Hope this helps everyone else, who wants to leave spaces between asteriks, while printing a rectangle and if there are any mistakes in my code let me know, because I'm a beginner myself.