DataFrame with MultiIndex to dict

Question

I have a dataframe with a MultiIndex. I am wondering whether I created the data frame in the correct manner (see below).

             01.01  02.01  03.01  04         


        

Answer 1

For converting whole dataframe to dictionary Try:

df.groupby(level=0).apply(lambda df: df.xs(df.name).to_dict()).to_dict()

{'bar': {'01.01': {'total1': 40, 'total2': 36},
  '02.01': {'total1': 52, 'total2': 85},
  '03.01': {'total1': 18, 'total2': 5},
  '04.01': {'total1': 11, 'total2': 92}},
 'baz': {'01.01': {'total1': 23, 'total2': 50},
  '02.01': {'total1': 39, 'total2': 49},
  '03.01': {'total1': 45, 'total2': 51},
  '04.01': {'total1': 70, 'total2': 65}},
 'foo': {'01.01': {'total1': 23, 'total2': 64},
  '02.01': {'total1': 97, 'total2': 56},
  '03.01': {'total1': 17, 'total2': 94},
  '04.01': {'total1': 97, 'total2': 45}},
 'qux': {'01.01': {'total1': 13, 'total2': 80},
  '02.01': {'total1': 73, 'total2': 8},
  '03.01': {'total1': 38, 'total2': 61},
  '04.01': {'total1': 4, 'total2': 50}}}

For converting one particular column, select before converting it to dictionary i.e

df.groupby(level=0).apply(lambda df: df.xs(df.name)[colname].to_dict()).to_dict()