Will the Compiler Optimize this out

Question

Say I have something like this in a C Code. I know you can use a #define instead, to make the compiler not compile it, but just out of curiosity I\'m asking if

Answer 1

Instead of asking such simple questions (where the only correct answer is "Try it out with your compiler") - why not just try it?

public class Test {
    public static void main(String[] args) {
        if (true) {
            System.out.println("Yep");
        }
        boolean var = false;
        if (var) {
            System.out.println("Nope");
        }
        final boolean var2 = false;
        if (var2) {
            System.out.println("Nope");
        }
    }
}

javac .\Test.java 
javap -c Test
Compiled from "Test.java"
public class Test {
  public Test();
    Code:
       0: aload_0
       1: invokespecial #1                  // Method java/lang/Object."<init>":()V
       4: return

  public static void main(java.lang.String[]);
    Code:
       0: getstatic     #2                  // Field java/lang/System.out:Ljava/io/PrintStream;
       3: ldc           #3                  // String Yep
       5: invokevirtual #4                  // Method java/io/PrintStream.println:(Ljava/lang/String;)V
       8: iconst_0
       9: istore_1
      10: iload_1
      11: ifeq          22
      14: getstatic     #2                  // Field java/lang/System.out:Ljava/io/PrintStream;
      17: ldc           #3                  // String Yep
      19: invokevirtual #4                  // Method java/io/PrintStream.println:(Ljava/lang/String;)V
      22: return
}

You don't need to know much about java/c# bytecode or assembly to be able to understand what's going on. And now go and try the same for C#..