Sorting a text file alphabetically (Python)

Question

I would like to sort the file \'shopping.txt\' in alphabetical order

shopping = open(\'shopping.txt\')
line=shopping.readline()
while len(line)!=0:
    print         


        

Answer 1

Use sorted function.

with open('shopping.txt', 'r') as r:
    for line in sorted(r):
        print(line, end='')

Answer 2

Just to show something different instead of doing this in python, you can do this from a command line in Unix systems:

sort shopping.txt -o shopping.txt

and your file is sorted. Of course if you really want python for this: solution proposed by a lot of other people with reading file and sorting works fine

Answer 3

An easy way to do this is using the sort() or sorted() functions.

lines = shopping.readlines()
lines.sort()

Alternatively:

lines = sorted(shopping.readlines())

The disadvantage is that you have to read the whole file into memory, though. If that's not a problem, you can use this simple code.