Sort List by alphabetical order

Question

I\'m trying to sort a list by alphabetical order and tried porting something i had in javascript to flutter. But it gives me an exception on String that it does not have the

Answer 1

Thanks to Remi's answer, I extracted this as a Function.

typedef Sort = int Function(dynamic a, dynamic b);
typedef SortF = Sort Function(String sortField);

SortF alphabetic = (String sortField) => (a, b){
  return a[sortField].toLowerCase().compareTo(b[sortField].toLowerCase());
};

SortF number = (String sortField) => (a, b) {
      return a[sortField].compareTo(b[sortField]);
    };

with this you can write.

list.sort(alphabetic('name')); //replace name with field name

list.sort(number('name')); //replace name with field name

Answer 2

late answer, i had a similar situation and here is how i solved it

     String a = 'towNnpBiDHRehMh4FhYAYShVFr62';
  String b = 'Yjeq9bA0spdZGmqlbr4J663LyvC3';
  String c = "RdeQo32uUwX3ftBeGm0nFChkzE52";
//if you try to sort the strings without converting them toLowercase ir uppercase you will get different results.
  List<String> _myBranchListName = [
    a.toLowerCase(),
    b.toLowerCase(),
    c.toLowerCase(),
  ];

  _myBranchListName.sort();
//if you want to add to strings from the result
  var userId = "${_myBranchListName[0]}" + "${_myBranchListName[1]}";
  print(userId);

  print(_myBranchListName);

Answer 3

I found the best way to sort a list alphabetically is this:

      List.sort((a, b) => a.toString().compareTo(b.toString()));

Answer 4

< and > is usually a shortcut to a compareTo method.

just use that method instead.

data.sort((a, b) {
  return a['name'].toLowerCase().compareTo(b['name'].toLowerCase());
});