How do I access elements from the outer loop from within nested loops?

Question

I have nested xsl:for loops:

Answer 1

The following could also be used :

    <xsl:for-each select="ns:attribute">
        <name><xsl:value-of select="ns:name" /></name>              
        <xsl:for-each select="ns:value">
        <value><xsl:value-of select="."/></value>       
        </xsl:for-each>
    </xsl:for-each>      

For parsing the XML document ..

 <ns:attribute>
      <ns:name>name</ns:name>
      <!--1 or more repetitions:-->
      <ns:value>Rahul</ns:value>
      <ns:value>Sushovan</ns:value>
</ns:attribute>

Answer 2

You can store the entire /Root/A structure in a variable, and make reference to that variable rather than creating a new variable for every attribute and subelement you need to access.

<xsl:for-each select="/Root/A/">
    <xsl:variable name="ROOT_A" select="."/>
    <xsl:for-each select="/Root/B/">
         <!-- Variable is accessed like this: $ROOT_A/@someAttribute
              Just like a normal XML node -->
    </xsl:for-each>
</xsl:for-each>

Answer 3

Welbog has answered it well - but just to note you appear to be doing a cartesion (cross) join - is that intentional? If you are trying to do a regular join (with a predicate etc), then you want want to look into <xsl:key/> - i.e. declare a key:

<xsl:key name="BIndex" match="/Root/B" use="SomeChildNode"/>

then consume in your predicate:

<xsl:for-each select="/Root/A/">
    <xsl:variable name="ROOT_A" select="."/>
    <xsl:for-each select="key('BIndex', LocalNode)">
     <!-- -->
    </xsl:for-each>
</xsl:for-each>

This should be equivalent to (but much faster than) the predicate:

    <xsl:for-each select="/Root/B[SomeChildNode = current()/LocalNode]">

If you are grouping the data, then look at Muenchian grouping