How to round integer in java

Question

I want to round the number 1732 to the nearest ten, hundred and thousand. I tried with Math round functions, but it was written only for float and double. How to do this for

Answer 1

I usually do it this way:

int num = 1732;
int roundedNum = Math.round((num + 9)/10 * 10);

This will give you 1740 as the result.

Hope this will help.

Answer 2

very simple. try this

int y = 173256457;int x = (y/10)*10; 

Now in this you can replace 10 by 100,1000 and so on....

Answer 3

Have you looked at the implementation of Mathutils.round() ? It's all based on BigDecimal and string conversions. Hard to imagine many approaches that are less efficient.

Answer 4

At nearest ten:

int i = 1986;
int result;

result = i%10 > 5 ? ((i/10)*10)+10 : (i/10)*10;

(Add zero's at will for hundred and thousand).

Answer 5

(int)(Math.round( 1732 / 10.0) * 10)

Math.round(double) takes the double and then rounds up as an nearest integer. So, 1732 will become 173.2 (input parameter) on processing by Math.round(1732 / 10.0). So the method rounds it like 173.0. Then multiplying it with 10 (Math.round( 1732 / 10.0) * 10) gives the rounded down answer, which is 173.0 will then be casted to int.

Answer 6

You could try:

int y = 1732;
int x = y - y % 10;

The result will be 1730.

Edit: This doesn't answer the question. It simply removes part of the number but doesn't "round to the nearest".