I\'m using a ListBox and adding objects to it.
The object contains 2 variables, let\'s say username and userid.
How can I add the objects in the list (like l
You can use the DisplayMember property of your listBox.
listbox.DisplayMember = "username";
There is also an equivalent property to define the actual value, that you could use to retrieve the userid. For example if you define your list like this:
listbox.DisplayMember = "username";
listbox.ValueMember = "userid";
var item1 = new MyType { username = "user1", userid = "id1" }; // Create an item for the list
listbox.Items.Add(item1); // Add the item
listbox.SelectedIndex = 0; // Selects the first item
Then you can reference the objects in the list by 3 different ways (item, value or text) like this:
MyObject newItem = (MyObject) listbox.SelectedItem; // Gets the selected MyType
// OR
string username = listbox.Text; // Gets the selected user name using the DisplayMember property of the listbox
// OR
string userid = listbox.SelectedValue; // Gets the selected user's userid using the ValueMember property of the listbox
You can also set the selected item the same 3 different ways:
listbox.SelectedItem = item1;
// OR
listbox.Text = item1.username;
// OR
listbox.SelectedValue = item1.userid;
Set the DataTextField
and DataValueField
ListBox a = new ListBox();
a.DataTextField = "username";
a.DataValueField = "userid";
To add using .Add
method you can use:
a.Items.Add(new ListItem() { Value = User.ID, Text = User.Name });
You can use the DisplayMember and ValueMember properties to display the UserName
property of your object and use its UserId
property as the list item value:
class YourItem
{
public string UserName { get; set; }
public string UserId { get; set; }
}
yourListBox.DisplayMember = "UserName";
yourListBox.ValueMember = "UserId";
yourListBox.Items.Add(new YourItem {
UserName = "FooName",
UserId = "FooId"
});
You can override "ToString" method.
class User
{
public string username { set; get; }
public string userid { set; get; }
public override string ToString()
{
return username;
}
}