Each GROUP BY expression must contain at least one column that is not an outer reference

Question

What am I doing wrong here? I am getting this error on:

SELECT LEFT(SUBSTRING(batchinfo.datapath, PATINDEX(\'%[0-9][0-9][0-9]%\', batchinfo.datapath), 8000),         


        

Answer 1

Here's a simple query to find company name who has a medicine type of A and makes more than 2.

SELECT CNAME 
FROM COMPANY 
WHERE CNO IN (
    SELECT CNO 
    FROM MEDICINE 
    WHERE type='A' 
    GROUP BY CNO HAVING COUNT(type) > 2
)