How do I convert wchar_t* to std::string?

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孤独总比滥情好 2020-12-09 08:16

I changed my class to use std::string (based on the answer I got here but a function I have returns wchar_t *. How do I convert it to std::string?

I tried this:

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  • 2020-12-09 08:20
    std::wstring ws( args.OptionArg() );
    std::string test( ws.begin(), ws.end() );
    
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  • 2020-12-09 08:23

    Following code is more concise:

    wchar_t wstr[500];
    char string[500];
    sprintf(string,"%ls",wstr);
    
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  • 2020-12-09 08:25

    This is an old question, but if it's the case you're not really seeking conversions but rather using the TCHAR stuff from Mircosoft to be able to build both ASCII and Unicode, you could recall that std::string is really

    typedef std::basic_string<char> string
    

    So we could define our own typedef, say

    #include <string>
    namespace magic {
    typedef std::basic_string<TCHAR> string;
    }
    

    Then you could use magic::string with TCHAR, LPCTSTR, and so forth

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  • 2020-12-09 08:26

    just for fun :-):

    const wchar_t* val = L"hello mfc";
    std::string test((LPCTSTR)CString(val));
    
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  • 2020-12-09 08:28

    You can convert a wide char string to an ASCII string using the following function:

    #include <locale>
    #include <sstream>
    #include <string>
    
    std::string ToNarrow( const wchar_t *s, char dfault = '?', 
                          const std::locale& loc = std::locale() )
    {
      std::ostringstream stm;
    
      while( *s != L'\0' ) {
        stm << std::use_facet< std::ctype<wchar_t> >( loc ).narrow( *s++, dfault );
      }
      return stm.str();
    }
    

    Be aware that this will just replace any wide character for which an equivalent ASCII character doesn't exist with the dfault parameter; it doesn't convert from UTF-16 to UTF-8. If you want to convert to UTF-8 use a library such as ICU.

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  • 2020-12-09 08:42

    You could just use wstring and keep everything in Unicode

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