Check if a string exists in an array case insensitively

Question

Declaration:

let listArray = [\"kashif\"]
let word = \"kashif\"

then this

contains(listArray, word) 

Ret

Answer 1

Swift 4

Just make everything (queries and results) case insensitive.

for item in listArray {
    if item.lowercased().contains(word.lowercased()) {
        searchResults.append(item)
    }
}

Answer 2

swift 5, swift 4.2 , use the code in the below.

let list = ["kAshif"]
let word = "Kashif"

if list.contains(where: { $0.caseInsensitiveCompare(word) == .orderedSame }) {
    print("contains is true")
}

Answer 3

My example

func updateSearchResultsForSearchController(searchController: UISearchController) {
    guard let searchText = searchController.searchBar.text else { return }
    let countries = Countries.getAllCountries()
    filteredCountries = countries.filter() {
        return $0.name.containsString(searchText) || $0.name.lowercaseString.containsString(searchText)
    }
    self.tableView.reloadData()
}

Answer 4

Try this:

let loword = word.lowercaseString
let found = contains(listArray) { $0.lowercaseString == loword }

Answer 5

you can use

word.lowercaseString 

to convert the string to all lowercase characters