Check if a string exists in an array case insensitively

Question

Declaration:

let listArray = [\"kashif\"]
let word = \"kashif\"

then this

contains(listArray, word) 

Ret

Answer 1

Expanding on @Govind Kumawat's answer

The simple comparison for a searchString in a word is:

word.range(of: searchString, options: .caseInsensitive) != nil

As functions:

func containsCaseInsensitive(searchString: String, in string: String) -> Bool {
    return string.range(of: searchString, options: .caseInsensitive) != nil
}

func containsCaseInsensitive(searchString: String, in array: [String]) -> Bool {
    return array.contains {$0.range(of: searchString, options: .caseInsensitive) != nil}
}

func caseInsensitiveMatches(searchString: String, in array: [String]) -> [String] {
    return array.compactMap { string in
        return string.range(of: searchString, options: .caseInsensitive) != nil
            ? string
            : nil
    }
}

Answer 2

Xcode 8 • Swift 3 or later

let list = ["kashif"]
let word = "Kashif"

if list.contains(where: {$0.caseInsensitiveCompare(word) == .orderedSame}) {
    print(true)  // true
}

alternatively:

if list.contains(where: {$0.compare(word, options: .caseInsensitive) == .orderedSame}) {
    print(true)  // true
}

if you would like to know the position(s) of the element in the array (it might find more than one element that matches the predicate):

let indices = list.indices.filter { list[$0].caseInsensitiveCompare(word) == .orderedSame }
print(indices)  // [0]

Answer 3

You can add an extension:

Swift 5

extension Array where Element == String {
    func containsIgnoringCase(_ element: Element) -> Bool {
        contains { $0.caseInsensitiveCompare(element) == .orderedSame }
    }
}

and use it like this:

["tEst"].containsIgnoringCase("TeSt") // true

Answer 4

For checking if a string exists in a array (case insensitively), please use

listArray.localizedCaseInsensitiveContainsString(word) 

where listArray is the name of array and word is your searched text

This code works in Swift 2.2

Answer 5

For checking if a string exists in a array with more Options(caseInsensitive, anchored/search is limited to start)

using Foundation range(of:options:)

let list = ["kashif"]
let word = "Kashif"


if list.contains(where: {$0.range(of: word, options: [.caseInsensitive, .anchored]) != nil}) {
    print(true)  // true
}

if let index = list.index(where: {$0.range(of: word, options: [.caseInsensitive, .anchored]) != nil}) {
    print("Found at index \(index)")  // true
}

Answer 6

SWIFT 3.0:

Finding a case insensitive string in a string array is cool and all, but if you don't have an index it can not be cool for certain situations.

Here is my solution:

let stringArray = ["FOO", "bar"]()
if let index = stringArray.index(where: {$0.caseInsensitiveCompare("foo") == .orderedSame}) {
   print("STRING \(stringArray[index]) FOUND AT INDEX \(index)")
   //prints "STRING FOO FOUND AT INDEX 0"                                             
}

This is better than the other answers b/c you have index of the object in the array, so you can grab the object and do whatever you please :)