Why is the error “Unable to find encoder for type stored in a Dataset” when encoding JSON using case classes?

Question

I\'ve written spark job:

object SimpleApp {
  def main(args: Array[String]) {
    val conf = new SparkConf().setAppName(\"Simple Application\").setMaster(\"l         


        

Answer 1

You have the same error if you add sqlContext.implicits._ and spark.implicits._ in SimpleApp (the order doesn't matter).

Removing one or the other will be the solution:

val spark = SparkSession
  .builder()
  .getOrCreate()

val sqlContext = spark.sqlContext
import sqlContext.implicits._ //sqlContext OR spark implicits
//import spark.implicits._ //sqlContext OR spark implicits

case class Person(age: Long, city: String)
val persons = ctx.read.json("/tmp/persons.json").as[Person]

Tested with Spark 2.1.0

The funny thing is if you add the same object implicits twice you will not have problems.

Answer 2

The error message says that the Encoder is not able to take the Person case class.

Error:(15, 67) Unable to find encoder for type stored in a Dataset.  Primitive types (Int, String, etc) and Product types (case classes) are supported by importing sqlContext.implicits._  Support for serializing other types will be added in future releases.

Move the declaration of the case class outside the scope of SimpleApp.

Answer 3

@Milad Khajavi

Define Person case classes outside object SimpleApp. Also, add import sqlContext.implicits._ inside main() function.