How to get numeric position of alphabets in java? [duplicate]

Answer 1

String str = "abcdef";
char[] ch  = str.toCharArray();
for(char c : ch){
    int temp = (int)c;
    int temp_integer = 96; //for lower case
    if(temp<=122 & temp>=97)
        System.out.print(temp-temp_integer);
}

Output:

123456

@Shiki for Capital/UpperCase letters use the following code:

String str = "DEFGHI";
char[] ch  = str.toCharArray();
for(char c : ch){
    int temp = (int)c;
    int temp_integer = 64; //for upper case
    if(temp<=90 & temp>=65)
        System.out.print(temp-temp_integer);
}

Output:

456789

Answer 2

First you need to write a loop to iterate over the characters in the string. Take a look at the String class which has methods to give you its length and to find the charAt at each index.

For each character, you need to work out its numeric position. Take a look at this question to see how this could be done.

Answer 3

This depends on the alphabet but for the english one, try this:

String input = "abc".toLowerCase(); //note the to lower case in order to treat a and A the same way
for( int i = 0; i < input.length(); ++i) {
   int position = input.charAt(i) - 'a' + 1;
}

Answer 4

Convert each character to its ASCII code, subtract the ASCII code for "a" and add 1. I'm deliberately leaving the code as an exercise.

This sounds like homework. If so, please tag it as such.

Also, this won't deal with upper case letters, since you didn't state any requirement to handle them, but if you need to then just lowercase the string before you start.

Oh, and this will only deal with the latin "a" through "z" characters without any accents, etc.

Answer 5

String word = "blah blah";

for(int i =0;i<word.length;++i)
{

if(Character.isLowerCase(word.charAt(i)){
System.out.print((int)word.charAt(i) - (int)'a'+1);
}
else{
System.out.print((int)word.charAt(i)-(int)'A' +1);
}
}

Answer 6

char letter;
for(int i=0; i<text.length(); i++)
{
    letter = text.charAt(i);
    if(letter>='A' && letter<='Z')
        System.out.println((int)letter - 'A'+1);
    if(letter>='a' && letter<= 'z')
        System.out.println((int)letter - 'a'+1);
}