Espresso: return boolean if view exists

Question

I am trying to check to see if a view is displayed with Espresso. Here is some pseudo code to show what I am trying:

if (!Espresso.onView(withId(R.id.someID)         


        

Answer 1

We need that functionality and I ended up implementing it below:

https://github.com/marcosdiez/espresso_clone

if(onView(withText("click OK to Continue")).exists()){ 
    doSomething(); 
} else { 
   doSomethingElse(); 
}

I hope it is useful for you.

Answer 2

I think to mimic UIAutomator you can do this:
(Though, I suggest rethinking your approach to have no conditions.)

ViewInteraction view = onView(withBlah(...)); // supports .inRoot(...) as well
if (exists(view)) {
     view.perform(...);
}

@CheckResult
public static boolean exists(ViewInteraction interaction) {
    try {
        interaction.perform(new ViewAction() {
            @Override public Matcher<View> getConstraints() {
                return any(View.class);
            }
            @Override public String getDescription() {
                return "check for existence";
            }
            @Override public void perform(UiController uiController, View view) {
                // no op, if this is run, then the execution will continue after .perform(...)
            }
        });
        return true;
    } catch (AmbiguousViewMatcherException ex) {
        // if there's any interaction later with the same matcher, that'll fail anyway
        return true; // we found more than one
    } catch (NoMatchingViewException ex) {
        return false;
    } catch (NoMatchingRootException ex) {
        // optional depending on what you think "exists" means
        return false;
    }
}

---

Also exists without branching can be implemented really simple:

onView(withBlah()).check(exists()); // the opposite of doesNotExist()

public static ViewAssertion exists() {
    return matches(anything());
}

Though most of the time it's worth checking for matches(isDisplayed()) anyway.