How to Remove Line Break in String

Question

I want to Remove the Line Break from the string if my string Ends with Line Break.

Sub linebreak(myString)
    If Len(myString) <> 0 Then
        If Rig         


        

Answer 1

As you are using Excel you do not need VBA to achieve this, you can simply use the built in "Clean()" function, this removes carriage returns, line feeds etc e.g:

=Clean(MyString)

Answer 2

Try with the following line:

CleanString = Application.WorksheetFunction.Clean(MyString)

Answer 3

None of the other answers (with one exception, see my edit) handle the case where there are multiple trailing carriage returns. If the goal is to make a function similar to "Trim" that removes carriage returns as well as spaces, you'll probably want it to be robust enough to remove as many as there are and not just one. Also, I'd recommend avoiding the use of the "Left" or "Right" functions in VBA since they do not exist in VB.Net. It may be necessary at some point to convert an Office VBA Macro to a VSTO COM Add-In so it's a good habit to avoid the use of functions that only exist in VBA.

Function RemoveTrailingWhiteSpace(s As String) As String
    RemoveTrailingWhiteSpace = s
    Dim StrLen As Long
    StrLen = Len(RemoveTrailingWhiteSpace)
    While (StrLen > 0 And (Mid(RemoveTrailingWhiteSpace, StrLen) = vbCr Or Mid(RemoveTrailingWhiteSpace, StrLen) = vbLf) Or Mid(RemoveTrailingWhiteSpace, StrLen) = " ")
        RemoveTrailingWhiteSpace = Mid(RemoveTrailingWhiteSpace, 1, StrLen - 1)
        StrLen = Len(RemoveTrailingWhiteSpace)
    Wend
End Function

Edit: I should clarify that there is another answer listed here that trims carriage returns and white space from both ends of the string, but it looked far more convoluted. This can be done fairly concisely.

Answer 4

str = Replace(str, vbLf, "")

This code takes all the line break's out of the code

if you just want the last one out:

If Right(str, 1) = vbLf Then str = Left(str, Len(str) - 1)

is the way how you tryed OK.

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Update:

line feed = ASCII 10, form feed = ASCII 12 and carriage return = ASCII 13. Here we see clearly what we all know: the PC comes from the (electric) typewriter

vbLf is Chr (10) and means that the cursor jumps one line lower (typewriter: turn the roller) vbCr is Chr (13) means the cursor jumps to the beginning (typewriter: pull back the roll)

In DOS, a line break is always VBCrLf or Chr (13) & Chr (10), in files anyway, but e.g. also with the text boxes in VB.

In an Excel cell, on the other hand, a line break is only VBLf, the second line then starts at the first position even without vbCr. With vbCrLf then go one cell deeper.

So it depends on where you read and get your String from. if you want to remove all the vbLf (Char(10)) and vbCr (Char(13)) in your tring, you can do it like that:

strText = Replace(Replace(strText, Chr(10), ""), Chr(13), "")

If you only want t remove the Last one, you can test on do it like this:

If Right(str, 1) = vbLf or Right(str, 1) = vbCr Then str = Left(str, Len(str) - 1)

Answer 5

Replace(yourString, vbNewLine, "", , , vbTextCompare)

Answer 6

vbCrLf and vbNewLine are actualy two characters long, so change to Right$(myString, 2)

Sub linebreak(myString)
    If Len(myString) <> 0 Then
        If Right$(myString, 2) = vbCrLf Or Right$(myString, 2) = vbNewLine Then 
            myString = Left$(myString, Len(myString) - 2)
        End If
    End If
End Sub