Finding words after keyword in python

Question

I want to find words that appear after a keyword (specified and searched by me) and print out the result. I know that i am suppose to use regex to do it, and i tried it out

Answer 1

Instead of using regexes you could just (for example) separate your string with str.partition(separator) like this:

mystring =  "hi my name is ryan, and i am new to python and would like to learn more"
keyword = 'name'
before_keyword, keyword, after_keyword = mystring.partition(keyword)
>>> before_keyword
'hi my '
>>> keyword
'name'
>>> after_keyword
' is ryan, and i am new to python and would like to learn more'

You have to deal with the needless whitespaces separately, though.

Answer 2

This will work out for u : work name\s\w+\s(\w+)

>>> s = 'hi my name is ryan, and i am new to python and would like to learn more'
>>> m = re.search('name\s\w+\s(\w+)',s)
>>> m.group(0)
'name is ryan'
>>>> m.group(1)
'ryan'

Answer 3

Your example will not work, but as I understand the idea:

regexp = re.compile("name(.*)$")
print regexp.search(s).group(1)
# prints " is ryan, and i am new to python and would like to learn more"

This will print all after "name" and till end of the line.

Answer 4

import re
s = "hi my name is ryan, and i am new to python and would like to learn more"
m = re.search("^name: (\w+)", s)

print m.group(1)

Answer 5

Without using regex, you can

• strip punctuation (consider making everything single case, including search term)

• split your text into individual words

• find index of searched word

• get word from array (index + 1 for word after, index - 1 for word before )

Code snippet:

import string
s = 'hi my name is ryan, and i am new to python and would like to learn more'
t = 'name'
i = s.translate(string.maketrans("",""), string.punctuation).split().index(t)
print s.split()[i+1]

>> is

---

For multiple occurences, you need to save multiple indices:

import string
s = 'hi my NAME is ryan, and i am new to NAME python and would like to learn more'
t = 'NAME'
il = [i for i, x in enumerate(s.translate(string.maketrans("",""), string.punctuation).split()) if x == t]
print [s.split()[x+1] for x in il]

>> ['is', 'python']

Answer 6

What you have used regarding your output:

re.search("name (\w+)", s)

What you have to use (match all):

re.search("name (.*)", s)