I have array and need to reverse it without Array.reverse
method, only with a for
loop.
var names:[String] = [\"Apple\", \"Microsof
I like simple codes.
var names:[String] = ["Apple", "Microsoft", "Sony", "Lenovo", "Asus"]
var reversedNames = [""]
for name in names {
reversedNames.insert(name, at: 0)
}
print(reversedNames)
Here is the most simpler way.
let names:[String] = ["Apple", "Microsoft", "Sony", "Lenovo", "Asus"]
var reversedNames = [String]()
for name in names {
reversedNames.insert(name, at: 0)
}
func reverse(array: inout [String]) {
if array.isEmpty { return }
var f = array.startIndex
var l = array.index(before: array.endIndex)
while f < l {
swap(array: &array, f, l)
array.formIndex(after: &f)
array.formIndex(before: &l)
}
}
private func swap( array: inout [String], _ i: Int, _ j: Int) {
guard i != j else { return }
let tmp = array[i]
array[i] = array[j]
array[j] = tmp
}
Or you can write extension of course
Like this, maybe:
names = names.enumerate().map() { ($0.index, $0.element) }.sort() { $0.0 > $1.0 }.map() { $0.1 }
Oh, wait.. I have to use for
loop, right? Then like this probably:
for (index, name) in names.enumerate().map({($0.index, $0.element)}).sort({$0.0 > $1.0}).map({$0.1}).enumerate() {
names[index] = name
}
You can use the swift3 document:
let names = ["Chris", "Alex", "Ewa", "Barry", "Daniella"]
let reversedNames = names.sorted(by: >)
// reversedNames is equal to:
// ["Ewa", "Daniella", "Chris", "Barry", "Alex"]
Here the code for swift 3
let array = ["IOS A", "IOS B", "IOS C"]
for item in array.reversed() {
print("Found \(item)")
}