I have a xml URL file in which there are white spaces i want to replace white spaces with %20.. how to do this????
SAXParserFactory spf = SAXParserFactory.ne
String s = "my string";
s=s.replaceAll(" ", "%20");
For anyone that needs space characters to be encoded as a %20
value instead of a +
value, use:
String encodedString = URLEncoder.encode(originalString,"UTF-8").replaceAll("\\+", "%20")
When you build your URL you should use URLEncoder to encode the parameters.
StringBuilder query = new StringBuilder();
query.append("gallery=");
query.append(URLEncoder.encode(value, "UTF-8"));
If you already have the whole URL in a String or a java.net.URL, you could grab the query part and rebuild while URLEncoding each parameter value.
Try this:
String temp = http://www.arteonline.mobi/iphone/output.php?gallery=MALBA%20-%20MUSEO%20DE%20ARTE%20LATINOAMERICANO%20DE%20BUENOS%20AIRES
temp = temp.replaceAll(" ", "%20");
URL sourceUrl = new URL(temp);
Try using URIUtil.encodePath method from the api org.apache.commons.httpclient.util.URIUtil
.
This should do the trick for you.
I guess you want to replace all spaces, not only white.
the simplest way is to use
"url_with_spaces".replaceAll(" ", "%20);
However you should consider also other characters in the url. See Recommended method for escaping HTML in Java