I\'ve got a function which fills an array of type sbyte[], and I need to pass this array to another function which accepts a parameter of type byte[].
Can I convert
You will have to copy the data (only reference-type arrays are covariant) - but we can try to do it efficiently; Buffer.BlockCopy
seems to work:
sbyte[] signed = { -2, -1, 0, 1, 2 };
byte[] unsigned = new byte[signed.Length];
Buffer.BlockCopy(signed, 0, unsigned, 0, signed.Length);
If it was a reference-type, you can just cast the reference without duplicating the array:
Foo[] arr = { new Foo(), new Foo() };
IFoo[] iarr = (IFoo[])arr;
Console.WriteLine(ReferenceEquals(arr, iarr)); // true
If you are using .NET 3.5+, you can use the following:
byte[] dest = Array.ConvertAll(sbyteArray, (a) => (byte)a);
Which is, I guess effectively copying all the data.
Note this function is also in .NET 2.0, but you'd have to use an anonymous method instead.
Yes, you can.
Since both byte
and sbyte
have the same binary representation there's no need to copy the data.
Just do a cast to Array, then cast it to byte[]
and it'll be enough.
sbyte[] signed = { -2, -1, 0, 1, 2 };
byte[] unsigned = (byte[]) (Array)signed;