Print list without brackets in a single row

Question

I have a list in Python e.g.

names = [\"Sam\", \"Peter\", \"James\", \"Julian\", \"Ann\"]

I want to print the array in a single line withou

Answer 1

I don't know if this is efficient as others but simple logic always works:

import sys
name = ["Sam", "Peter", "James", "Julian", "Ann"]
for i in range(0, len(names)):
    sys.stdout.write(names[i])
    if i != len(names)-1:
        sys.stdout.write(", ")

Output:

Sam, Peter, James, Julian, Ann

Answer 2

print(', '.join(names))

This, like it sounds, just takes all the elements of the list and joins them with ', '.

Answer 3

print(*names)

this will work in python 3 if you want them to be printed out as space separated. If you need comma or anything else in between go ahead with .join() solution

Answer 4

This is what you need

", ".join(names)

Answer 5

General solution, works on arrays of non-strings:

>>> print str(names)[1:-1]
'Sam', 'Peter', 'James', 'Julian', 'Ann'

Answer 6

','.join(list) will work only if all the items in the list are strings. If you are looking to convert a list of numbers to a comma separated string. such as a = [1, 2, 3, 4] into '1,2,3,4' then you can either

str(a)[1:-1] # '1, 2, 3, 4'

or

str(a).lstrip('[').rstrip(']') # '1, 2, 3, 4'

although this won't remove any nested list.

To convert it back to a list

a = '1,2,3,4'
import ast
ast.literal_eval('['+a+']')
#[1, 2, 3, 4]