Call Perl script from Python

Question

I\'ve got a Perl script that I want to invoke from a Python script. I\'ve been looking all over, and haven\'t been successful. I\'m basically trying to call the Perl scrip

Answer 1

If you just want to open a pipe to a perl interpreter, you're on the right track. The only thing I think you're missing is that the perl script itself is not an executable. So you need to do this:

var = "/some/file/path/"
pipe = subprocess.Popen(["perl", "./uireplace.pl", var], stdin=subprocess.PIPE)
pipe.stdin.write(var)
pipe.stdin.close()

Answer 2

Just do:

var = "/some/file/path/"
pipe = subprocess.Popen(["perl", "uireplace.pl", var])

Answer 3

I Hope this can help you. Do not know how to do that otherwise.

Answer 4

Would you like to pass var as a parameter, on stdin or both? To pass it as a parameter, use

subprocess.call(["./uireplace.pl", var])

To pipe it to stdin, use

pipe = subprocess.Popen("./uireplace.pl", stdin=subprocess.PIPE)
pipe.communicate(var)

Both code snippets require uireplace.pl to be executable. If it is not, you can use

pipe = subprocess.Popen(["perl", "./uireplace.pl"], stdin=subprocess.PIPE)
pipe.communicate(var)

Answer 5

You could try the subprocess.call() method. It won't return output from the command you're invoking, but rather the return code to indicate if the execution was successful.

var = "/some/file/path"
retcode = subprocess.call(["./uireplace.pl", var])
if retcode == 0:
    print("Passed!")
else:
    print("Failed!")

Make sure you're Perl script is executable. Otherwise, you can include the Perl interpreter in your command (something like this):

subprocess.call(["/usr/bin/perl", "./uireplace.pl", var])