TileProvider method getTile - need to translate x and y to lat/long

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北荒
北荒 2020-12-08 11:12

I’m porting an iOS app to Android, and using Google Maps Android API v2. The application needs to draw a heatmap overlay onto the map.

So far, it looks

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  • 2020-12-08 11:56

    On zoom level 0, there is only one tile (x=0,y=0). On next zoom level number of tiles are quadrupled (doubled on x and y).

    This means on zoom level W, x may be a value in range <0, 1 << W).

    From documentation:

    The coordinates of the tiles are measured from the top left (northwest) corner of the map. At zoom level N, the x values of the tile coordinates range from 0 to 2N - 1 and increase from west to east and the y values range from 0 to 2N - 1 and increase from north to south.

    You can achieve this using simple calculations.

    For longitude this is straightforward :

    double longitudeMin = (((double) x) / (1 << zoom)) * 360 - 180;
    double longitudeMax = (((double) x + 1) / (1 << zoom)) * 360 - 180;
    longitudeMax = Double.longBitsToDouble(Double.doubleToLongBits(longitudeMax) - 1); // adjust
    

    Here x is first scaled into <0,1), then into <-180,180).

    The max value is adjusted, so it doesn't overlap with the next area. You may skip this.

    For latitude this will be a bit harder, because Google Maps use Mercator projection.

    First you scale y just like it was in range <-180,180). Note that the values need to be reversed.

    double mercatorMax = 180 - (((double) y) / (1 << zoom)) * 360;
    double mercatorMin = 180 - (((double) y + 1) / (1 << zoom)) * 360;
    

    Now you use a magical function that does Mercator projection (from SphericalMercator.java):

    public static double toLatitude(double mercator) {
        double radians = Math.atan(Math.exp(Math.toRadians(mercator)));
        return Math.toDegrees(2 * radians) - 90;
    }
    
    latitudeMax = SphericalMercator.toLatitude(mercatorMax);
    latitudeMin = SphericalMercator.toLatitude(mercatorMin);
    latitudeMin = Double.longBitsToDouble(Double.doubleToLongBits(latitudeMin) + 1);
    

    This was was typed from memory and was not tested in any way, so if there is an error there, please put a comment and I will fix it.

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  • 2020-12-08 12:03

    MaciejGórski if you don't mind (if you do, I will remove this post) I compiled your code into ready to use method:

    private LatLngBounds boundsOfTile(int x, int y, int zoom) {
        int noTiles = (1 << zoom);
        double longitudeSpan = 360.0 / noTiles;
        double longitudeMin = -180.0 + x * longitudeSpan;
    
        double mercatorMax = 180 - (((double) y) / noTiles) * 360;
        double mercatorMin = 180 - (((double) y + 1) / noTiles) * 360;
        double latitudeMax = toLatitude(mercatorMax);
        double latitudeMin = toLatitude(mercatorMin);
    
        LatLngBounds bounds = new LatLngBounds(new LatLng(latitudeMin, longitudeMin), new LatLng(latitudeMax, longitudeMin + longitudeSpan));
        return bounds;
    }
    
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  • 2020-12-08 12:08

    This worked for me:

    double n = Math.pow(2, zoom);
    double longitudeMin = x/n * 360 -180;
    double lat_rad = Math.atan(Math.sinh(Math.PI * (1 - 2 * y/n)));
    double latitudeMin = lat_rad * 180/Math.PI;
    
    double longitudeMax = (x + 1)/n * 360 -180;
    lat_rad = Math.atan(Math.sinh(Math.PI * (1 - 2 * (y + 1)/n)));
    double latitudeMax = lat_rad * 180/Math.PI;
    

    References: http://wiki.openstreetmap.org/wiki/Slippy_map_tilenames

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