PHP REGEX: Get domain from URL

Question

What I want

---

I want to get from a URL the domain part so from http://example.com/ -> example.com

Answer 1

I think the following regexp might answers your question.

This diagram explains how it works, or rather why it works :-)

$regexp = '/.*\/\/([^\/:]+).*/';

// www.stackoverflow.com
echo preg_replace($regexp, '$1', 'http://www.stackoverflow.com/questions/ask');

// google.de
echo preg_replace($regexp, '$1', 'http://google.de/?q=hello');

// it works for the other input tests too ;-)

Answer 2

Best way i think:

preg_match('/(http(|s)):\/\/(.*?)\//si',  'http://www.example.com/page/?bla=123#!@#$%^&*()_+', $output);
// $output[0] ------------>  https://www.example.com/

Answer 3

I use:

$domain = parse_url('http://' . str_replace(array('https://', 'http://'), '', $url), PHP_URL_HOST);

Because parse_url doesn't return host key when schema is missing in $url.

Answer 4

There's no need to use a regex for this. PHP has an inbuilt function to do just this. Use parse_url():

$domain = parse_url($url, PHP_URL_HOST);

Answer 5

Here's my quick and dirty solution.

http://([^/]+).*

I haven't tested it, but it should grab anything between the http:// and the first slash.

Answer 6

if (preg_match('/http:\/\/([^\/]+)\//i', $target_string, $matches)) {
  $domain = $matches[1];
}