How do I get the full path of the current file's directory?

Question

I want to get the current file\'s directory path. I tried:

>>> os.path.abspath(__file__)
\'C:\\\\python27\\\\test.py\'

But how can

Answer 1

## IMPORT MODULES
import os

## CALCULATE FILEPATH VARIABLE
filepath = os.path.abspath('') ## ~ os.getcwd()
## TEST TO MAKE SURE os.getcwd() is EQUIVALENT ALWAYS..
## ..OR DIFFERENT IN SOME CIRCUMSTANCES

Answer 2

To keep the migration consistency across platforms (macOS/Windows/Linux), try:

path = r'%s' % os.getcwd().replace('\\','/')

Answer 3

import os
print os.path.dirname(__file__)

Answer 4

Using Path is the recommended way since Python 3:

from pathlib import Path
print("File      Path:", Path(__file__).absolute())
print("Directory Path:", Path().absolute())  

Documentation: pathlib

Note: If using Jupyter Notebook, __file__ doesn't return expected value, so Path().absolute() has to be used.

Answer 5

I found the following commands will all return the full path of the parent directory of a Python 3.6 script.

Python 3.6 Script:

#!/usr/bin/env python3.6
# -*- coding: utf-8 -*-

from pathlib import Path

#Get the absolute path of a Python3.6 script
dir1 = Path().resolve()  #Make the path absolute, resolving any symlinks.
dir2 = Path().absolute() #See @RonKalian answer 
dir3 = Path(__file__).parent.absolute() #See @Arminius answer 

print(f'dir1={dir1}\ndir2={dir2}\ndir3={dir3}')

Explanation links: .resolve(), .absolute(), Path(file).parent().absolute()

Answer 6

Let's assume you have the following directory structure: -

main/ fold1 fold2 fold3...

folders = glob.glob("main/fold*")

for fold in folders:
    abspath = os.path.dirname(os.path.abspath(fold))
    fullpath = os.path.join(abspath, sch)
    print(fullpath)