Difference of keywords 'typename' and 'class' in templates?

后端 未结 5 575
南方客
南方客 2020-11-22 16:37

For templates I have seen both declarations:

template < typename T >
template < class T >

What\'s the difference?

And

相关标签:
5条回答
  • 2020-11-22 17:09

    typename and class are interchangeable in the basic case of specifying a template:

    template<class T>
    class Foo
    {
    };
    

    and

    template<typename T>
    class Foo
    {
    };
    

    are equivalent.

    Having said that, there are specific cases where there is a difference between typename and class.

    The first one is in the case of dependent types. typename is used to declare when you are referencing a nested type that depends on another template parameter, such as the typedef in this example:

    template<typename param_t>
    class Foo
    {
        typedef typename param_t::baz sub_t;
    };
    

    The second one you actually show in your question, though you might not realize it:

    template < template < typename, typename > class Container, typename Type >
    

    When specifying a template template, the class keyword MUST be used as above -- it is not interchangeable with typename in this case (note: since C++17 both keywords are allowed in this case).

    You also must use class when explicitly instantiating a template:

    template class Foo<int>;
    

    I'm sure that there are other cases that I've missed, but the bottom line is: these two keywords are not equivalent, and these are some common cases where you need to use one or the other.

    0 讨论(0)
  • 2020-11-22 17:11

    This piece of snippet is from c++ primer book. Although I am sure this is wrong.

    Each type parameter must be preceded by the keyword class or typename:

    // error: must precede U with either typename or class
    template <typename T, U> T calc(const T&, const U&);
    

    These keywords have the same meaning and can be used interchangeably inside a template parameter list. A template parameter list can use both keywords:

    // ok: no distinction between typename and class in a template parameter list
    template <typename T, class U> calc (const T&, const U&);
    

    It may seem more intuitive to use the keyword typename rather than class to designate a template type parameter. After all, we can use built-in (nonclass) types as a template type argument. Moreover, typename more clearly indicates that the name that follows is a type name. However, typename was added to C++ after templates were already in widespread use; some programmers continue to use class exclusively

    0 讨论(0)
  • 2020-11-22 17:13
    1. No difference
    2. Template type parameter Container is itself a template with two type parameters.
    0 讨论(0)
  • 2020-11-22 17:22

    While there is no technical difference, I have seen the two used to denote slightly different things.

    For a template that should accept any type as T, including built-ins (such as an array )

    template<typename T>
    class Foo { ... }
    

    For a template that will only work where T is a real class.

    template<class T>
    class Foo { ... }
    

    But keep in mind that this is purely a style thing some people use. Not mandated by the standard or enforced by compilers

    0 讨论(0)
  • 2020-11-22 17:33

    For naming template parameters, typename and class are equivalent. §14.1.2:

    There is no semantic difference between class and typename in a template-parameter.

    typename however is possible in another context when using templates - to hint at the compiler that you are referring to a dependent type. §14.6.2:

    A name used in a template declaration or definition and that is dependent on a template-parameter is assumed not to name a type unless the applicable name lookup finds a type name or the name is qualified by the keyword typename.

    Example:

    typename some_template<T>::some_type
    

    Without typename the compiler can't tell in general whether you are referring to a type or not.

    0 讨论(0)
提交回复
热议问题