How to generate random strings that match a given regexp?

Question

Duplicate:

Random string that matches a regexp

No, it isn\'t. I\'m looking for an easy and universal method, one that I could actu

Answer 1

if your only criteria are that your method is easy and universal, then there ain't nothing easier or more universal than brute force. :)

for (i = 0; i < 10; ++i) {
    do {
        var str = generateRandomString();
    } while (!myRegex.match(str));
    myListOfGoodStrings.push(str);
}

Of course, this is a very silly way to do things and mostly was meant as a joke.

I think your best bet would be to try writing your own very basic parser, teaching it just the things which you're expecting to encounter (eg: letter and number ranges, repeating/optional characters... don't worry about look-behinds etc)

Answer 2

The universality criterion is impossible. Given the regular expression "^To be, or not to be -- that is the question:$", there will not be ten unique random strings that match.

For non-degenerate cases:

moonshadow's link to Perl's String::Random is the answer. A Perl program that reads a RegEx from stdin and writes the output from ten invocations of String::Random to stdout is trivial. Compile it to either a Windows or Unix exe with Perl2exe and invoke it from PHP, Python, or whatever.

Also see Random Text generator based on regex

Answer 3

One rather ugly solution that may or may not be practical is to leverage an existing regex diagnostics option. Some regex libraries have the ability to figure out where the regex failed to match. In this case, you could use what is in effect a form of brute force, but using one character at a time and trying to get longer (and further-matching) strings until you got a full match. This is a very ugly solution. However, unlike a standard brute force solution, it failure on a string like ab will also tell you whether there exists a string ab.* which will match (if not, stop and try ac. If so, try a longer string). This is probably not feasible with all regex libraries.

On the bright side, this kind of solution is probably pretty cool from a teaching perspective. In practice it's probably similar in effect to a dfa solution, but without the requirement to think about dfas.

Note that you won't want to use random strings with this technique. However, you can use random characters to start with if you keep track of what you've tested in a tree, so the effect is the same.

Answer 4

Parse your regular expression into a DFA, then traverse your DFA randomly until you end up in an accepting state, outputting a character for each transition. Each walk will yield a new string that matches the expression.

This doesn't work for "regular" expressions that aren't really regular, though, such as expressions with backreferences. It depends on what kind of expression you're after.

Answer 5

Take a look at Perl's String::Random.