How to use ng-repeat with filter and $index?

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南笙 2020-12-08 07:33

I want to use ng-repeat in Angular, while I only want to output some elements of the array. An Example:

ng-repeat=\"item in items | filter:($index%3 == 0)\"
         


        
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6条回答
  • 2020-12-08 07:52

    Create a custom filter, for example:

    filter('modulo', function(){
      return function (arr, div, val) {
          return arr.filter(function(item, index){
              return index % div === (val || 0);
          })
      };
    });
    

    Then change the ng-repeat to:

    <ul ng-repeat="item in items | modulo:3">
    

    Or filter by (index % 3 === 1) like:

    <ul ng-repeat="item in items | modulo:3:1"> 
    

    http://jsfiddle.net/Tc34P/2/

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  • 2020-12-08 07:56

    All the precedent answers will work, but if you want to use a filter, you can also define it yourself, like in this fiddle : http://jsfiddle.net/DotDotDot/58y7u/

    .filter('myFilter', function(){
        return function(data, parameter){
            var filtered=[];
            for(var i=0;i<data.length;i++){
                    if(i%parameter==0)
                        filtered.push(data[i]);
            }
            return filtered;
        }
    });
    

    and then call it like this :

    ng-repeat='item in items | myFilter:3'
    

    (I added extra complexity with a parameter, if you want to change it quickly to even numbers for example)

    Have fun

    ++

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  • 2020-12-08 07:56

    An alternate approach to solving this creates a new "list" (I don't know the proper term in this context) in the ng-repeat. This new list can then be referred to within the scope

    <ul class="example-animate-container">
      <li class="animate-repeat" ng-repeat="friend in filteredFriends = ((friends | filter:q:strict) | orderBy:'age')" ng-if="$index % 2 == 0">
        [{{$index + 1}}] {{filteredFriends[$index].name}} who is {{filteredFriends[$index].age}} years old.
        <span ng-if="$index+1 < filteredFriends.length">[{{$index + 2}}] {{filteredFriends[$index+1].name}} who is {{filteredFriends[$index+1].age}} years old.</span>
      </li>
    </ul>
    

    The ng-if on the span wrapping the second half prevents the base text from being shown when the previous element is the last element of the list.

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  • 2020-12-08 07:57

    I suggest filtering with a function:

    ng-repeat"item in filterItems(items)"
    

    And on the Controller:

    $scope.filterItems= function(items) {
        var result = {};
        angular.forEach(items, function(item) {
           // if item is something.. add to result
        });
        return result;
    }
    
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  • 2020-12-08 08:02

    In your code, filter apply on 'items' array, not on each array item, that's why it does not work as you expect.

    Instead, you can use ng-show (or ng-if):

    <ul>
        <li ng-repeat="item in items" ng-show="$index % 3 == 0">{{item}}</li>
    </ul>
    

    See: http://jsfiddle.net/H7d26

    EDIT: Use ng-if directive if you do not want to add invisible dom elements:

    <ul>
        <li ng-repeat="item in items" ng-if="$index % 3 == 0">{{item}}</li>
    </ul>
    
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  • 2020-12-08 08:07

    What you need to do is find the index of "item" in $scope.items. See below

    ng-repeat"item in items | filter:(items.indexOf(item)%3 == 0)
    

    So a real world example (for others who come across this solution) would be.

    <div ng-repeat="item in filtered = (items | filter:customfilter | orderBy:customsort)">
        <div> This is number {{items.indexOf(item)}} in the items list on the scope.</div>
    </div>
    

    The above example will get the correct position regardless of the sorting or filtering

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