Best practice for saving an entire collection?

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生来不讨喜
生来不讨喜 2020-12-08 06:55

Say that I have a Collection and I\'ve made changes to many of its Models. What\'s the best way to save all of the changes using a single HTTP request?

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  • 2020-12-08 07:29

    Usually REST backends handle single instance creation/update. You would need to change that to accept an array of objects.

    That said, on the client side, you would need to go directly to the Backbone.sync function

    Backbone.sync = function(method, model, options)
    

    In this case your model should be an array of model. The method should be "create" or "save" and the options take the same type of options as a jQuery ajax call (error, success, etc.)

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  • 2020-12-08 07:33

    I'm going to do the Wrong Thing here and quote Wikipedia regarding proper RESTful practices: a PUT to example.com/resources should replace the entire collection with another collection. Based on this, when we had to support editing multiple items simultaneously, we wrote up this contract.

    1. The client sends {"resources": [{resource1},{resource2}]}
    2. The server replaces the entire collection with the new information from the client, and returns the information after it's been persisted: {"resources": [{"id":1,...},{"id":2,...}]}

    We wrote the server half of the contract in Rails, but here's the client half (in CoffeeScript, sorry!):

    class ChildElementCollection extends Backbone.Collection
      initialize: ->
        @bind 'add', (model) -> model.set('parent_id', @parent.id)
    
      url: -> "#{@parent.url()}/resources" # let's say that @parent.url() == '/parent/1'
      save: ->
        response = Backbone.sync('update', @, url: @url(), contentType: 'application/json', data: JSON.stringify(children: @toJSON()))
        response.done (models) => @reset models.resources
    

    I thought this was a lot easier to implement then overriding Backbone.sync. One comment on the code, our collections were always child objects, which should explain why the code sets a "parent_id" whenever an object is added to the collection, and how the root of the URL is the parent's URL. If you have root-level collections that you want to modify, then just remove the @parent business.

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  • 2020-12-08 07:44

    This code adds a new method to the collection prototype just to call the save method of those models that had changed. It worked for me:

    Backbone.Collection.prototype.saveAll = function(options) {
     return $.when.apply($, _.map(this.models, function(m) {
       return m.hasChanged() ? m.save(null, options).then(_.identity) : m;
     }));
    };
    

    Gist link: https://gist.github.com/julianitor/701c677279bac1529b88

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  • 2020-12-08 07:45

    You should extend Backbone.Collection, giving it a save() method that would check each of its models hasChanged().

    Then it should call Backbone.sync, which you'll probably have to extend a little into a custom sync function. If you do use a custom Backbone.sync function, then be sure to set it on your collection.

    var CollectionSync = function(method, model, [options]) {
        // do similar things to Backbone.sync
    }
    
    var MyCollection = Backbone.Collection.extend({
        sync: CollectionSync,
        model: MyModel,
        getChanged: function() {
            // return a list of models that have changed by checking hasChanged()
        },
        save: function(attributes, options) {
            // do similar things as Model.save
        }
    });
    

    A different approach (using a model to represent the collection) is here: "How" to save an entire collection in Backbone.js - Backbone.sync or jQuery.ajax?

    I also like https://stackoverflow.com/a/7986982/137067

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