Java Code for calculating Leap Year

Question

I am following \"The Art and Science of Java\" book and it shows how to calculate a leap year. The book uses ACM Java Task Force\'s library.

Here is the code the boo

Answer 1

boolean leapYear = ( ( year % 4 ) == 0 );

Answer 2

With the course of : TestMyCode Programming assignment evaluator, that one of the exercises was this kind of issue, I wrote this answer:

import java.util.Scanner;

public class LeapYear {

    public static void main(String[] args) {
        Scanner reader = new Scanner(System.in);
        System.out.println("Type a year: ");

        int year = Integer.parseInt(reader.nextLine());

        if (year % 400 == 0 && year % 100 == 0 && year % 4 == 0) {
            System.out.println("The year is a leap year");
        } else
         if (year % 4 == 0 && year%100!=0 ) {
            System.out.println("The year is a leap year");
        } else 
        {
            System.out.println("The year is not a leap year");
        }

    }
}

Answer 3

You can ask the GregorianCalendar class for this:

boolean isLeapyear = new GregorianCalendar().isLeapYear(year);

Answer 4

easiest way ta make java leap year and more clear to understandenter code here

import  java.util.Scanner;

class que19{

public static void main(String[] args) {

    Scanner input=new Scanner(System.in);

    double a;

    System.out.println("enter the year here ");
    a=input.nextDouble();
    if ((a % 4 ==0 ) && (a%100!=0) || (a%400==0)) {
        System.out.println("leep year");

    }
    else {
        System.out.println("not a leap year");
    }
}

}

Answer 5

Pseudo code from Wikipedia translated into the most compact Java

(year % 400 == 0) || ((year % 4 == 0) && (year % 100 != 0))

Answer 6

Your code, as it is, without an additional class, does not appear to work for universal java. Here is a simplified version that works anywhere, leaning more towards your code.

import java.util.*;
public class LeapYear {
    public static void main(String[] args) {
        int year;
        {
            Scanner scan = new Scanner(System.in);
            System.out.println("Enter year: ");
            year = scan.nextInt();

            if ((year % 4 == 0) && year % 100 != 0) {
                System.out.println(year + " is a leap year.");
            } else if ((year % 4 == 0) && (year % 100 == 0)
                    && (year % 400 == 0)) {
                System.out.println(year + " is a leap year.");
            } else {
                System.out.println(year + " is not a leap year.");
            }
        }
    }
}

Your code, in context, works just as well, but note that book code always works, and is tested thoroughly. Not to say yours isn't. :)