An Interesting Simplifaciton Operator in Ruby

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一向
一向 2020-11-22 16:50

So, what I wanna do is to find (ab / bc) = (a / c), while a,b,c are digits. Example: (16 / 64) = (1 / 4) I\'m only allowed to do this with while loop (I can\'t use class, de

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