How to remove the last character from a bash grep output

Question

COMPANY_NAME=`cat file.txt | grep \"company_name\" | cut -d \'=\' -f 2` 

outputs something like this

\"Abc Inc\";

Answer 1

cat file.txt | grep "company_name" | cut -d '=' -f 2 | cut -d ';' -f 1

Answer 2

This will remove the last character contained in your COMPANY_NAME var regardless if it is or not a semicolon:

echo "$COMPANY_NAME" | rev | cut -c 2- | rev