How do I get the month and day with leading 0's in SQL? (e.g. 9 => 09)

Question

DECLARE @day CHAR(2)

SET @day = DATEPART(DAY, GETDATE())

PRINT @day

If today was the 9th of December, the above would print \"9\".

I want

Answer 1

For SQL Server 2012 and up , with leading zeroes:

 SELECT FORMAT(GETDATE(),'MM') 

without:

SELECT    MONTH(GETDATE())

Answer 2

SELECT RIGHT('0' 
             + CONVERT(VARCHAR(2), Month( column_name )), 2) 
FROM   table 

Answer 3

select right('0000' + cast(datepart(year, GETDATE()) as varchar(4)), 4) + '-'+ + right('00' + cast(datepart(month, GETDATE()) as varchar(2)), 2) + '-'+ + right('00' + cast(datepart(day, getdate()) as varchar(2)), 2) as YearMonthDay

Answer 4

Pad it with 00 and take the right 2:

DECLARE @day CHAR(2)

SET @day = RIGHT('00' + CONVERT(NVARCHAR(2), DATEPART(DAY, GETDATE())), 2)

print @day

Answer 5

DECLARE @day CHAR(2)

SET @day = right('0'+ cast(day(getdate())as nvarchar(2)),2)

print @day

Answer 6

Leading 0 day

SELECT FORMAT(GetDate(), 'dd')