Simple jQuery, PHP and JSONP example?

Question

I am facing the same-origin policy problem, and by researching the subject, I found that the best way for my particular project would be to use JSONP to do cross-origin requ

Answer 1

To make the server respond with a valid JSONP array, wrap the JSON in brackets () and preprend the callback:

echo $_GET['callback']."([{'fullname' : 'Jeff Hansen'}])";

Using json_encode() will convert a native PHP array into JSON:

$array = array(
    'fullname' => 'Jeff Hansen',
    'address' => 'somewhere no.3'
);
echo $_GET['callback']."(".json_encode($array).")";

Answer 2

Simple jQuery, PHP and JSONP example is below:

window.onload = function(){
	$.ajax({
		cache: false,
		url: "https://jsonplaceholder.typicode.com/users/2",
		dataType: 'jsonp',
		type: 'GET',
		success: function(data){
			console.log('data', data)
		},
		error: function(data){
			console.log(data);
		}
	});
};

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

Answer 3

When you use $.getJSON on an external domain it automatically actions a JSONP request, for example my tweet slider here

If you look at the source code you can see that I am calling the Twitter API using .getJSON.

So your example would be: THIS IS TESTED AND WORKS (You can go to http://smallcoders.com/javascriptdevenvironment.html to see it in action)

//JAVASCRIPT

$.getJSON('http://www.write-about-property.com/jsonp.php?callback=?','firstname=Jeff',function(res){
    alert('Your name is '+res.fullname);
});

//SERVER SIDE
  <?php
 $fname = $_GET['firstname'];
      if($fname=='Jeff')
      {
          //header("Content-Type: application/json");
         echo $_GET['callback'] . '(' . "{'fullname' : 'Jeff Hansen'}" . ')';

      }
?>

Note the ?callback=? and +res.fullname

Answer 4

More Suggestion

JavaScript:

$.ajax({
        url: "http://FullUrl",
        dataType: 'jsonp',
        success: function (data) {

            //Data from the server in the in the variable "data"
            //In the form of an array

        }

});

PHP CallBack:

<?php

$array = array(
     '0' => array('fullName' => 'Meni Samet', 'fullAdress' => 'New York, NY'),
     '1' => array('fullName' => 'Test 2', 'fullAdress' => 'Paris'),
);

if(isset ($_GET['callback']))
{
    header("Content-Type: application/json");

    echo $_GET['callback']."(".json_encode($array).")";

}
?>

Answer 5

$.ajax({

        type:     "GET",
        url: '<?php echo Base_url("user/your function");?>',
        data: {name: mail},
        dataType: "jsonp",
        jsonp: 'callback',
        jsonpCallback: 'chekEmailTaken',
        success: function(msg){
    }
});
return true;

In controller:

public function ajax_checkjp(){
$checkType = $_GET['name'];
echo $_GET['callback']. '(' . json_encode($result) . ');';  
}

Answer 6

First of all you can't make a POST request using JSONP.

What basically is happening is that dynamically a script tag is inserted to load your data. Therefore only GET requests are possible.

Furthermore your data has to be wrapped in a callback function which is called after the request is finished to load the data in a variable.

This whole process is automated by jQuery for you. Just using $.getJSON on an external domain doesn't always work though. I can tell out of personal experience.

The best thing to do is adding &callback=? to you url.

At the server side you've got to make sure that your data is wrapped in this callback function.

ie.

echo $_GET['callback'] . '(' . $data . ')';

EDIT:

Don't have enough rep yet to comment on Liam's answer so therefore the solution over here.

Replace Liam's line

 echo "{'fullname' : 'Jeff Hansen'}";

with

 echo $_GET['callback'] . '(' . "{'fullname' : 'Jeff Hansen'}" . ')';