Compare given date with today

Question

I have following

$var = \"2010-01-21 00:00:00.0\"

I\'d like to compare this date against today\'s date (i.e. I\'d like to know if this

Answer 1

Some given answers don't have in consideration the current day!

Here it is my proposal.

$var = "2010-01-21 00:00:00.0"
$given_date = new \DateTime($var);

if ($given_date == new \DateTime('today')) {
  //today
}

if ($given_date < new \DateTime('today')) {
  //past
}

if ($given_date > new \DateTime('today')) {
  //future
}

Answer 2

Here you go:

function isToday($time) // midnight second
{
    return (strtotime($time) === strtotime('today'));
}

isToday('2010-01-22 00:00:00.0'); // true

---

Also, some more helper functions:

function isPast($time)
{
    return (strtotime($time) < time());
}

function isFuture($time)
{
    return (strtotime($time) > time());
}

Answer 3

If you do things with time and dates Carbon is you best friend;

Install the package then:

$theDay = Carbon::make("2010-01-21 00:00:00.0");

$theDay->isToday();
$theDay->isPast();
$theDay->isFuture();
if($theDay->lt(Carbon::today()) || $theDay->gt(Carbon::today()))

lt = less than, gt = greater than

As in the question:

$theDay->gt(Carbon::today()) ? true : false;

and much more;

Answer 4

Compare date time objects:

(I picked 10 days - Anything older than 10 days is "OLD", else "NEW")

$now   = new DateTime();
$diff=date_diff($yourdate,$now);
$diff_days = $diff->format("%a");
if($diff_days > 10){
    echo "OLD! " . $yourdate->format('m/d/Y');
}else{
    echo "NEW! " . $yourdate->format('m/d/Y');
}

Answer 5

To complete BoBby Jack, the use of DateTime OBject, if you have php 5.2.2+ :

if(new DateTime() > new DateTime($var)){
    // $var is before today so use it

}

Answer 6

Expanding on Josua's answer from w3schools:

//create objects for the dates to compare
$date1=date_create($someDate);
$date2=date_create(date("Y-m-d"));
$diff=date_diff($date1,$date2);
//now convert the $diff object to type integer
$intDiff = $diff->format("%R%a");
$intDiff = intval($intDiff);
//now compare the two dates
if ($intDiff > 0)  {echo '$date1 is in the past';}
else {echo 'date1 is today or in the future';}

I hope this helps. My first post on stackoverflow!