How to find all Siblings of the currently selected DOM object

Question

What is the perfect way to find all nextSiblings and previousSiblings in JavaScript. I tried few ways but not getting accurate solution. If any element is selected, I need t

Answer 1

back to 2017:
Maybe there is a better answer but that good and a little bit cleaner

function sibiling(dom, query) {
   var doms = dom.parentElement.querySelectorAll(query);
   return [].slice.call(doms).filter( d => d != dom);
}

Answer 2

This is an update to @subhaze's answer.

This code uses the matches DOM method which is supported in modern browsers:

Demo

function matches(elem, filter) {
  if (elem && elem.nodeType === 1) {
    if (filter) {
      return elem.matches(filter);
    }
    return true;
  }
  return false;
}

// this will start from the current element and get all of
// the next siblings
function getNextSiblings(elem, filter) {
  var sibs = [];
  while (elem = elem.nextSibling) {
    if (matches(elem, filter)) {
      sibs.push(elem);
    }
  }
  return sibs;
}

// this will start from the current element and get all the
// previous siblings
function getPreviousSiblings(elem, filter) {
  var sibs = [];
  while (elem = elem.previousSibling) {
    if (matches(elem, filter)) {
      sibs.push(elem);
    }
  }
  return sibs;
}

// this will start from the first child of the current element's
// parent and get all the siblings
function getAllSiblings(elem, filter) {
  var sibs = [];
  elem = elem.parentNode.firstChild;
  while (elem = elem.nextSibling) {
    if (matches(elem, filter)) {
      sibs.push(elem);
    }
  } 
  return sibs;
}

Use these functions as follows:

var elem = document.querySelector('#test');

// find all the "div" and "span" siblings
var after = getNextSiblings(elem, 'div, span');

// find previous siblings with ".list-item" class
var index = getPreviousSiblings(elem, '.list-item');

// get all siblings with a title attribute
var allSibs = getAllSiblings(elem, '[title]');

Answer 3

Just my two cents here, I made a couple of functions to get all the previos and the next siblings of any element.

const getPreviousAll = element => {
  const previousAllFound = [];
  const getPrevious = element => {
    if (element !== null) {
      previousAllFound.push(element);
      const previousFound = element.previousElementSibling;
      if (previousFound !== null) {
        getPrevious(previousFound);
      }
    }
  };
  getPrevious(element.previousElementSibling);
  return previousAllFound;
};
const getNextAll = element => {
  const target = element;
  const nextAllFound = [];
  const getAll = element => {
    if (element !== null) {
      nextAllFound.push(element);
      const nextFound = element.nextElementSibling;
      if (nextFound !== null) {
        getAll(nextFound);
      }
    }
  };
  getAll(element.nextElementSibling);
  return nextAllFound;
};

You just have to call this functions with a node that you can get by getElementById.

Answer 4

This is a bit more winded of a solution but allows you to create a filter on how you get siblings.

There are three functions to get only previous, only next, or all. This could be improved but decent starting point if you need more control on what types of siblings you want to collect. Thought it might be worth adding.

Working Example

get all next siblings

//this will start from the current element and get all of the next siblings

function getNextSiblings(elem, filter) {
    var sibs = [];
    while (elem = elem.nextSibling) {
        if (elem.nodeType === 3) continue; // text node
        if (!filter || filter(elem)) sibs.push(elem);
    }
    return sibs;
}

get all previous siblings

//this will start from the current element and get all the previous siblings

function getPreviousSiblings(elem, filter) {
    var sibs = [];
    while (elem = elem.previousSibling) {
        if (elem.nodeType === 3) continue; // text node
        if (!filter || filter(elem)) sibs.push(elem);
    }
    return sibs;
}

get all siblings

//this will start from the first child of the current element's parent and get all the siblings

function getAllSiblings(elem, filter) {
    var sibs = [];
    elem = elem.parentNode.firstChild;
    do {
        if (elem.nodeType === 3) continue; // text node
        if (!filter || filter(elem)) sibs.push(elem);
    } while (elem = elem.nextSibling)
    return sibs;
}

example filter to apply to above functions

// Example filter only counts divs and spans but could be made more complex
function exampleFilter(elem) {
    switch (elem.nodeName.toUpperCase()) {
        case 'DIV':
            return true;
        case 'SPAN':
            return true;
        default:
            return false;
    }
}

HTML and testing output

HTML

<div id='test'>
    <div id='test2'>asdf</div>
    <br /> sdf
    <div>asdfasdf<span>asdf</span></div>
    <div>a</div>
    <span>a</span>
    <br />
    <div>d</div>
    <hr/>
</div>

JavaScript

var elem;
elem = document.getElementById('test2');

//with filter alerts 4
alert( getNextSiblings( elem, exampleFilter ).length );

// no filter, alerts 7
elem = document.getElementById('test2');// put elem back to what it was
alert( getNextSiblings( elem ).length );

// alerts 0
elem = document.getElementById('test2');// put elem back to what it was
alert( getPreviousSiblings( elem, exampleFilter ).length );

// alerts 5
elem = document.getElementById('test2');// put elem back to what it was
alert( getAllSiblings( elem, exampleFilter ).length );

Answer 5

Here is a very short and simple way to do it with ES6:

function getAllSiblings(element, parent) {
        const children = [...parent.children];
        return children.filter(child => child !== element);
    }

This will return all children of the parent node that are not the element.