Determining if all attributes on a javascript object are null or an empty string

Question

What is the most elegant way to determine if all attributes in a javascript object are either null or the empty string? It should work for an arbitrary number of attributes

Answer 1

This works with me perfectly:

checkProperties(obj) {
  let arr = [];
  for (let key in obj) {
    arr.push(obj[key] !== undefined && obj[key] !== null && obj[key] !== "");
  }
  return arr.includes(false);
}

This will return true or false if there is at-least one value is empty or something like that.

Answer 2

let obj = { x: null, y: "hello", z: 1 };
let obj1 = { x: null, y: "", z: 0 };

!Object.values(obj).some(v => v);
// false

!Object.values(obj1).some(v => v);
// true

Answer 3

Based on adeneo's answer, I created a single line condition. Hope it will be helpful to someone.

var test = {
  "email": "test@test.com",
  "phone": "1234567890",
  "name": "Test",
  "mobile": "9876543210",
  "address": {
      "street": "",
      "city": "",
      "state": "",
      "country": "",
      "postalcode": "r"
  },
  "website": "www.test.com"
};

if (Object.keys(test.address).every(function(x) { return test.address[x]===''||test.address[x]===null;}) === false) {
   console.log('has something');
} else {
   console.log('nothing');
}

You can test it https://jsfiddle.net/4uyue8tk/2/