Django and query string parameters

Question

Assuming I have a \'get_item\' view, how do I write the URL pattern for the following php style of URL?

http://example.com/get_item/?id=2&type=foo&co         


        

Answer 1

See this pattern

url(r'^get_item$', get_item)

And your view will look like

def get_item(request):
    id = int(request.Get.get('id'))

Answer 2

You just need to change your url pattern to:

(r'^get_item/$', get_item)

And your view code will work. In Django the url pattern matching is used for the actual path not the querystring.

Answer 3

Make your pattern like this:

(r'^get_item/$', get_item)

And in your view:

def get_item(request):
    id = int(request.GET.get('id'))
    type = request.GET.get('type', 'default')

Though for normal detail views etc. you should put the id/slug in the url and not in the query string! Use the get parameters eg. for filtering a list view, for determining the current page etc...