Python one-line “for” expression

Question

I\'m not sure if I need a lambda, or something else. But still, I need the following:

I have an array = [1,2,3,4,5]. I need to put this array, for insta

Answer 1

Even array2.extend(array1) will work.

Answer 2

Using elements from the list 'A' create a new list 'B' with elements, which are less than 10

Option 1:

A = [1, 1, 2, 3, 5, 8, 13, 4, 21, 34, 9, 55, 89]

B = []
for i in range(len(A)):
    if A[i] < 10:
        B.append(A[i])
print(B)

Option 2:

A = [1, 1, 2, 3, 5, 8, 13, 4, 21, 34, 9, 55, 89]

B = [A[i] for i in range(len(A)) if A[i] < 10]
print(B)

Result: [1, 1, 2, 3, 5, 8, 4, 9]

Answer 3

If you're trying to copy the array:

array2 = array[:]

Answer 4

If you really only need to add the items in one array to another, the '+' operator is already overloaded to do that, incidentally:

a1 = [1,2,3,4,5]
a2 = [6,7,8,9]
a1 + a2
--> [1, 2, 3, 4, 5, 6, 7, 8, 9]

Answer 5

for item in array: array2.append (item)

Or, in this case:

array2 += array

Answer 6

The keyword you're looking for is list comprehensions:

>>> x = [1, 2, 3, 4, 5]
>>> y = [2*a for a in x if a % 2 == 1]
>>> print(y)
[2, 6, 10]