Java: parse int value from a char

Question

I just want to know if there\'s a better solution to parse a number from a character in a string (assuming that we know that the character at index n is a number).

Answer 1

Try the following:

str1="2345";
int x=str1.charAt(2)-'0';
//here x=4;

if u subtract by char '0', the ASCII value needs not to be known.

Answer 2

String a = "jklmn489pjro635ops";

int sum = 0;

String num = "";

boolean notFirst = false;

for (char c : a.toCharArray()) {

    if (Character.isDigit(c)) {
        sum = sum + Character.getNumericValue(c);
        System.out.print((notFirst? " + " : "") + c);
        notFirst = true;
    }
}

System.out.println(" = " + sum);

Answer 3

That's probably the best from the performance point of view, but it's rough:

String element = "el5";
String s;
int x = element.charAt(2)-'0';

It works if you assume your character is a digit, and only in languages always using Unicode, like Java...

Answer 4

Try Character.getNumericValue(char).

String element = "el5";
int x = Character.getNumericValue(element.charAt(2));
System.out.println("x=" + x);

produces:

x=5

The nice thing about getNumericValue(char) is that it also works with strings like "el٥" and "el५" where ٥ and ५ are the digits 5 in Eastern Arabic and Hindi/Sanskrit respectively.

Answer 5

String element = "el5";
int x = element.charAt(2) - 48;

Subtracting ascii value of '0' = 48 from char

Answer 6

By simply subtracting by char '0'(zero) a char (of digit '0' to '9') can be converted into int(0 to 9), e.g., '5'-'0' gives int 5.

String str = "123";

int a=str.charAt(1)-'0';